I have used the following references to obtain the necessary data for my calculations.
https://www.convertunits.com/from/cmH2O/to/kPa
1 cm H20 = 0.0980665 kPa (or 0.014223343 psi)
https://www.engineeringtoolbox.com/air-a...d_462.html
atmospheric pressure at 0 ft elevation = 101 kPa
atmospheric pressure at 10,000 ft elevation = 69.7 kPa
so:
31.3 kPa atmospheric pressure change per 10,000 ft elevation change
or 0.00313 kPa atmospheric pressure change per 1 ft elevation change
Since 1 ft change in elevation changes the atmospheric pressure by 0.00313 kPA,
and 1 cm H2O equals 0.0980665 kPa,
then a change of 1 cm H2O changes the elevation by 31.3 ft
here's the calculation: 0.0980665/0.00313=31.3
Table of equivalent elevation changes at CPAP pressures
cm H20 kPa elevation change (ft)
1 0.0980665 31.3
2 0.196133 62.7
3 0.2941995 94.0
4 0.392266 125.3
5 0.4903325 156.7
6 0.588399 188.0
7 0.6864655 219.3
8 0.784532 250.6
9 0.8825985 282.0
10 0.980665 313.3
11 1.0787315 344.6
12 1.176798 376.0
13 1.2748645 407.3
14 1.372931 438.6
15 1.4709975 470.0
16 1.569064 501.3
17 1.6671305 532.6
18 1.765197 564.0
19 1.8632635 595.3
20 1.96133 626.6
As an example, using a CPAP pressure of 10cm H20 would be similar to descending about 313 ft in elevation.
I hope all my figures, calculations and conclusions are correct but would appreciate peer review.